A metallic meter stick moves with a velocity of 2 ms –1 in a direction perpendicular to its length and perpendicular to a uniform magnetic field of magnitude 0.2 T. Find the emf induced between the ends of the stick.

Question

Philoid · Accepted Answer

Given:

Velocity of meter stick

Intensity of magnetic field

Length of stick =1m

We know that,

motional emf produced due to a conductor of length l moving with velocity v in a magnetic field B is given by

Since v⃗ and B⃗ are perpendicular and their cross product is parallel to l⃗, eqn.(i) reduces to

Putting the values of v, B and l we get,

Therefore, emf induced between the ends of a stick is 0.4V

A metallic meter stick moves with a velocity of 2 ms–1 in a direction perpendicular to its length and perpendicular to a uniform magnetic field of magnitude 0.2 T. Find the emf induced between the ends of the stick.

A metallic meter stick moves with a velocity of 2 ms^–1 in a direction perpendicular to its length and perpendicular to a uniform magnetic field of magnitude 0.2 T. Find the emf induced between the ends of the stick.