A right-angled triangle abc, made from a metallic wire, moves at a uniform speed v in its plane as shown in figure. A uniform magnetic field B exists in the perpendicular direction. Find the emf induced (a) in the loop abc, (b) in the segment bc, (c) in the segment ac and (d) in the segment ab.

Question

Philoid · Accepted Answer

Given:

Speed of right-angled triangle =v

We know that,

motional emf produced due to a conductor of length l moving with velocity v in a magnetic field B is given by

…. (i)

(a) for loop abc since the flux of magnetic field through the triangle does not change hence the emf induced in loop abc is zero

Therefore, emf induced in loop abc is zero

(b) in the segment bc

bc is perpendicular to velocity. emf induced in the segment bc is given by

Therefore, emf induced in segment bc is vB(bc)

(c) in the segment ac

ac is parallel to velocity. Emf induced in the segment ac is given by

Therefore, emf induced in the segment ac is zero

(d) in the segment ab

the effective length of ab perpendicular to velocity is given by bc (-ĵ)

emf induced in the segment ab is given by

Therefore, emf induced in the segment ab is vB(bc)

A right-angled triangle abc, made from a metallic wire, moves at a uniform speed v in its plane as shown in figure. A uniform magnetic field B exists in the perpendicular direction. Find the emf induced(a) in the loop abc,(b) in the segment bc,(c) in the segment ac and(d) in the segment ab.

A right-angled triangle abc, made from a metallic wire, moves at a uniform speed v in its plane as shown in figure. A uniform magnetic field B exists in the perpendicular direction. Find the emf induced
(a) in the loop abc,

(b) in the segment bc,

(c) in the segment ac and

(d) in the segment ab.