A wire of length 10 cm translates in a direction making an angle of 60° with its length. The plane of motion is perpendicular to a uniform magnetic field of 1.0 T that exists in the space. Find the emf induced between the ends of the rod if the speed of translation is 20 cm s –1 .

Question

Philoid · Accepted Answer

Given:

Length of the wire=10cm

Angle of length of wire with velocity=60°

Magnetic field intensity=1.0T

Speed of wire v=20cm/s =0.2m/s

(a) we know that,

motional emf produced due to a conductor of length l moving with velocity v in a magnetic field B is given by

It is given that plane of motion is perpendicular to electric field i.e. angle between v⃗ and B⃗ =90°

And the angle between velocity and length of wire=60°

We take only that component of length vector which is perpendicular to velocity vector

Putting the values of B, v, l we get

Therefore the emf induced in the rod is

A wire of length 10 cm translates in a direction making an angle of 60° with its length. The plane of motion is perpendicular to a uniform magnetic field of 1.0 T that exists in the space. Find the emf induced between the ends of the rod if the speed of translation is 20 cm s–1.

A wire of length 10 cm translates in a direction making an angle of 60° with its length. The plane of motion is perpendicular to a uniform magnetic field of 1.0 T that exists in the space. Find the emf induced between the ends of the rod if the speed of translation is 20 cm s^–1.