Let Fpp, Fpn and Fnn denote the magnitude of the nuclear force by a proton on a proton, by a proton on a neutron and by a neutron on a neutron respectively. When the separation is 1fm,

As the distance of separation is equal, so the forces that will act between the particles will be same as because


Mass of neutron=Mass of proton=


Thus, the forces can be represented as,


Fpp=Fnn=Fpn=



Therefore, as the distance of separation is equal, thus they will have same magnitude of forces.


So, (b) is the correct answer.

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