How much energy is released in the following reaction:
7Li + p → α + α.
Atomic mass of 7Li = 7.0160 u and that of 4He = 4.0026 u.
Given,
Atomic mass of 7Li = 7.0160 u
Mass of proton = 1.007276 u
Atomic mass of 4He = Mass of α particle = 4.0026 u
∴
So, ΔM = 0.018076u
Binding Energy [Where
]
Hence, the binding energy for the reaction is 16.83 MeV