The half-life of 40 K is 1.30 × 10 9 y. A sample of 1.00 g of pure KCl gives 160 counts s –1 . Calculate the relative abundance of 40 K (fraction of 40 K present) in natural potassium.

Question

Philoid · Accepted Answer

Given, t_1/2= 1.3× 10⁹ y

Activity, A= 160 counts s^–1

As

As 6.023×10²³ atoms are present in 40g

⇒

∴ The relative abundance of ⁴⁰K in natural potassium= (2×0.00063×100) % = 0.12%

The half-life of 40K is 1.30 × 109 y. A sample of 1.00 g of pure KCl gives 160 counts s–1. Calculate the relative abundance of 40K (fraction of 40K present) in natural potassium.

The half-life of ⁴⁰K is 1.30 × 10⁹ y. A sample of 1.00 g of pure KCl gives 160 counts s^–1. Calculate the relative abundance of ⁴⁰K (fraction of ⁴⁰K present) in natural potassium.