Calculate the energy released by 1g of natural uranium assuming 200 MeV is released in each fission event and that the fissionable isotope 235U has an abundance of 0.7% by weight in natural uranium.

Given, 1g of sample contains 0.007g 235U

And 235g of 235U contains 6.023× 1023 atoms


0.007g contains × 0.007 atoms


1 atom releases 200MeV energy


So, total energy= Energy released per atom× total no. of atoms



1