Taking the Bohr radius as a0 = 53pm, the radius of Li++ ion in its ground state, on the basis of Bohr’s model, will be about
As we know that the radius of an atom in its ground state is given by the formula where a0 is Bohr’s radius, and Z is atomic number.
Now just putting the values in above formula, we have
a0 = 53pm and also we know the atomic number of lithium is 3.
Hence rpm ≈ 18pm.
Therefore option (c) is correct.