A nuclide 1 is said to be the mirror isobar of nuclide 2 if Z1 =N2 and Z2 =N1.
(a) What nuclide is a mirror isobar of
?
(b) Which nuclide out of the two mirror isobars have greater binding energy and why?
(a) The mirror isobar of
is ![]()
(b)
has a greater binding energy than that of ![]()
Explanation
(a).
Mirror isobars are isobars whose mass number is same and the number of protons of
is equal to the number of the neutrons of
and the number of neutron of
is equal to the proton of the
. Therefore, the mass number of both the elements is
![]()
So according to mirror isomers
![]()
Then the mass number can also be formed as
![]()
Now to find the mirror isobar of nuclide
, we know that mass number of sodium (Na) = 23, and another similar case is that of Magnesium (Mg) = 23, with sodium has 11 proton and 12 neutron and magnesium with 12 proton and 11 neutron.
(b).
To find the binding energy of the elements of Sodium and Magnesium; we use the formula for calculation of Binding energy from mass defect.
To find the value of atomic mass of an element we use:
![]()
where
is the number of proton,
is the number of neutrons, the mass of a single proton =
, the mass of a single neutron is ![]()
So firstly for Sodium,
We need the actual mass of Sodium which is ![]()
The atomic mass of Sodium is from the calculation of proton and neutrons is
![]()
To convert the mass defect into
we multiply it by ![]()
Therefore, the Binding Energy of the element Sodium is
![]()
Similarly for Magnesium, we get the Binding Energy as
We need the actual mass of Magnesium which is ![]()
The atomic mass of Magnesium is from the calculation of proton and neutrons is
![]()
To convert the mass defect into
we multiply it by
Therefore, the Binding Energy of the element Magnesium is
![]()
Hence, as we can see that the Binding energy of magnesium is greater than that of Sodium, the is another reason apart from the value is because of the number of proton present in the nucleus, even number of protons tends to have more Binding Energy than that of odd number of protons.