We can find the solution using Kohlrausch law of independent migration of ions. This law states that limiting molar conductivity of an electrolyte is equal to the sum of the individual limiting molar conductivities of the anion and cation of the electrolyte. There are three equations mentioned in the options which are acid-base neutralization reactions. They are –

HNO₃ + NaOH → NaNO₃ + H₂O

HCl + NaOH → NaCl + H₂O

HCl + NH₄OH → NH₄Cl + H₂O

Λ^o_m(H2O) = Λ^o_m(HNO3) + Λ^o_m(NaOH) – Λ^o_m(NaNO3)

Λ^o_m(H2O) =Λ^o_m(HCl) + Λ^o_m(NaOH) – Λ^o_m(NaCl)

Λ^o_m(H2O) =Λ^o_m(HCl) + Λ^o_m(NH4OH) – Λ^o_m(NH4Cl)

The correct options are (i), (iii) and (iv).