Wavelengths of different radiations are given below : λ(A) = 300 nm λ(B) = 300 μm λ(c) = 3 nm λ (D) 30 A ° Arrange these radiations in the increasing order of their energies.

Question

Philoid · Accepted Answer

According to Planck’s quantum theory, energy is related to the frequency of radiation by :

E = h × Frequency

=

So, E 1/ λ

Hence, the relation b/w energy and wavelength are inversely proportional, therefore lesser the wavelength higher will be the energy of the radiation.

For the given wavelengths

λ(A) = 300 nm = 300 x 10^-9 m = 3 x 10 ^-7 m

λ(B) = 300 μm = 3 00 x 10^-6 = 3 x 10^-4

λ(c) = 3 nm = 3 x 10 ^{– 9}

λ (D) 30 A° = 3 X 10 ^{- 9}

the increasing order of the given wavelengths : λ(c) = λ (D) <λ(A)< λ(B)

hence the increasing order of energy will be the opposite: λ(B)< λ(A:<λ(c) = λ (D)

Wavelengths of different radiations are given below :λ(A) = 300 nmλ(B) = 300 μmλ(c) = 3 nmλ (D) 30 A°Arrange these radiations in the increasing order of their energies.

Wavelengths of different radiations are given below :
λ(A) = 300 nm

λ(B) = 300 μm

λ(c) = 3 nm

λ (D) 30 A°

Arrange these radiations in the increasing order of their energies.