When BCl 3 is treated with water, it hydrolyses and forms [B[OH] 4 ] - only whereas AlCl 3 in acidified aqueous solution forms [Al (H 2 O) 6 ] 3+ ion. Explain what is the hybridisation of boron and aluminium in these species?

Question

Philoid · Accepted Answer

The reaction of the BCl₃ with water occurs in two steps:

The Boron in the ion involves one 2s orbital and 3 2p orbitals.

Thus, the hybridization of the Boron atom is sp³.

The 6 H₂O molecules get attach with Al i.e. donate 6 electron pair to the 3s,3p and 3d orbital of Al³⁺ ion.

Thus, the hybridization of the Al atom in species is sp³d².

When BCl3 is treated with water, it hydrolyses and forms [B[OH]4]- only whereas AlCl3 in acidified aqueous solution forms [Al (H2O)6]3+ ion. Explain what is the hybridisation of boron and aluminium in these species?

When BCl₃ is treated with water, it hydrolyses and forms [B[OH]₄]^- only whereas AlCl₃ in acidified aqueous solution forms [Al (H₂O)₆]³⁺ ion. Explain what is the hybridisation of boron and aluminium in these species?