In a coaxial, straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero


According to Ampere’s Law:
Where,

B is the magnetic field,


dl is the current element,


μ0 is the permeability of free space


i is the current flowing in the conductor



Magnetic field outside the cable: B = BI+BO
BI and BO are the magnetic field of the inner conductor and outer cable respectively.
Due to wire,
R is the radius of the wire.


Thus, option (A) is the correct option.


Magnetic field inside the inner conductor:


B. dl =μo I (I=0(inside the wire))


Magnetic field between the two conductors and inside the outer conductor.


B. dl =μo I


On integrating the length element over the complete loop, we get dl= 2π r


B.2π r=μo I


On solving the above equation for B, we get



Thus, option A and B is the correct option.

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