Figure shows a square loop ABCD with edge length a. The resistance of the wire ABC is r and that of ADC is 2r. Find the magnetic field B at the centre of the loop assuming uniform wires.
Resistance of wire ADC is given twice that of wire ABC. hence current flow through ADC is half of ABC
i.e.,
--------------------(1)
also ---------------(2)
Equating equations (1) and (2), we get
and
Hence, magnetic field at centre O due to wire AB and BC
and magnetic field at centre o due to wire AD and DC
Also , so
Hence net magnetic field at centre O