Consider the situation described in the previous problem. Suppose the current i enters the loop at the point A and leaves it at the point B. Find the magnetic field at the centre of the loop.

Question

Philoid · Accepted Answer

Magnetic vector B due to BC and due to AD at PT equal and opposite.

Hence net vector B = 0

Similarly, due to AB and CD at P = 0

∴ The net vector B at the centre of the square loop = 0