A square loop PQRS carrying a current of 6.0 A is placed near long wire carrying 10 A as shown in figure (35-E10). A Show that the magnetic force acting on the part PQ is equal and opposite to that on the part RS. B Find the magnetic force on the square loop.
Here, current in the wire is
Current in the loop,
Force on an element dx in the arm PQ a distance x away is
similarly, force on RS is,
Hence,.
B distance of PS from wire,
distance of PS from RQ,
Force on element PS is
towards right
Now distance of RQ from wire,
distance of RQ from PS,
similarly, force on RQ is
towards left
Net force,