Calculate the volume of water required to dissolve 0.1 g lead (II) chloride to get a saturated solution. (K sp of PbCl 2 = 3.2 × 10 -8 , atomic mass of Pb = 207 u).

Question

Philoid · Accepted Answer

Given, K_sp of PbCl₂ =3.2 ×10^-8

The equation of disassociation of PbCl₂ will be-

K_sp = [Pb²⁺] [Cl^-] ²

= (x) × (2x) ² = 4x³

4x³ =3.2 × 10^-8

x=2 ×10^-3 mol/L

Solubility = molar mass (PbCl₂) × 2 × 10^-3

=556 × 10^-3 =0.556 g/L

The required volume to get a saturated solution of PbCl₂ is 0.1798 L

Calculate the volume of water required to dissolve 0.1 g lead (II) chloride to get a saturated solution. (Ksp of PbCl2 = 3.2 × 10-8, atomic mass of Pb = 207 u).

Calculate the volume of water required to dissolve 0.1 g lead (II) chloride to get a saturated solution. (K_sp of PbCl₂ = 3.2 × 10^-8, atomic mass of Pb = 207 u).