For the reaction: N 2 (g) + 3H 2 (g) ⇋ 2NH 3 (g) Equilibrium constant K c = Some reactions are written below in Column I and their Equilibrium constants in terms of K c are written in Column II. Match the following reactions with the corresponding Equilibrium constant Column I (Reaction) Column II (Equilibrium constant)

Question

Philoid · Accepted Answer

Given, N₂ (g) + 3H₂ (g) ⇋ 2NH₃ (g)

(i) 2N₂ (g) + 6H₂ (g) ⇋ 4NH₃ (g) - (d) K²_c

Explanation: The Equilibrium constant depends on the stoichiometric coefficient of reactants and products. Here the no of moles is getting double therefore if the initial value of Equilibrium constant was K_c so it will increase two times i.e. K²_c.

(ii) 2NH₃ (g) ⇋ N₂ (g) + 3H₂ (g) - 1/K_c

Explanation: In this equation, the reaction is in reverse order therefore if the initial value of Equilibrium constant was K_c then now it will also get inversed for the given reaction and will become 1/K_c because Equilibrium constant for the reverse reaction is the inverse of the Equilibrium constant for the reaction in the forward direction.

(iii) N₂ (g) + H₂ (g) ⇋ NH₃ (g) - (b) K^1/2_c

Explanation: Here the stoichiometric coefficient are changed by multiplying throughout by 1/2 so if the initial value of Equilibrium constant was K_c then now it will get multiplied by 1/2 throughout for the given reaction and the value of K^’_c will become Kⁿ_c here n=1/2 so K^’_c= K^1/2_c.