A hydrogen atom in a state having a binding energy of 0.85eV makes transition to a state with excitation energy 10.2eV. A. Identify the quantum number n of the upper and the lower energy states involved in the transition. B. Find the wavelength of the emitted radiation.

Question

Philoid · Accepted Answer

A. We know that the binding energy is given by,

Now, energy in the first state is given as, E=0.85eV

So,

Again,

Thus, the states are 4 and 2.

B. If we take n₁ as n and n₂ as m and thus calculate the wavelength as follows,

or, λ=487nm