A hydrogen atom in state n=6 makes two successive transitions and reaches the ground state. In the first transition a photon of 1.13eV is emitted. A. Find the energy of the photon emitted in the second transition B. What is the value of n in the intermediate state?

As the hydrogen atom reaches the ground state from n=6, thus,


A. Energy at n=6,


Again, energy in the ground state is, (for hydrogen atom)


Since the atom makes 2 successive transitions, so the energy in the second transition can be found out by subtracting the energy in the ground state and energy in the 6th state and adding up the first transition energy.


So,



(The negative sign shows that energy is being given for making the transitions from 6th state to the ground state)


B. Energy in the intermediate state is given as=1.13+0.3777777=1.507eV


Thus, to calculate the n, we have,





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