Electrons are emitted by a hot filament and are accelerated by an electric field as shown in figure. The two stops at the left ensure that the electrons beam has a uniform cross-section.

Electric field is in the direction form right to left.
Let velocity of an electron at stop A is ![]()
velocity of an electron at stop A is ![]()
Potentials are increased in the opposite direction of electric field.
So ![]()
Potential energy of the electron at point A is
![]()
Potential energy of the electron at point B is
![]()
![]()
Because ![]()
Kinetic energy of an electron at point A is ![]()
Kinetic energy of an electron at point B is ![]()
Applying conservation of mechanical energy , we get
![]()
(Mechanical energy =potential energy+kinetic energy)
(Because![]()
Speed of electron is more at stop B than stop A. Option A is correct.