25Vm^-1

Given,

Length, l of the wire= 2m

Resistance, R of the wire=5 Ω

Current I, passing through the wire= 10A

Formula used,

From electrostatics, we know that Electric field, E is

Or it can be written as

Where l is the distance over which potential difference V has an effect

Solution,

We know that the potential difference, V in the wire with current I passing and with a resistance R is

By substituting the given values in the above expression, we get V as

Substituting this value of potential difference in eqn.1, we can find the electric field,

So,

Or

Hence the electric field existing inside the wire is 25Vm^-1