The potential difference between the terminals of a 6.0 V battery is 7.2 V when it is being charged by a current of 2.0 A. What is the internal resistance of the battery?
0.6Ω
Given,
The potential difference across the setup, V= 7.2V
The emf of the cell, E=6V
The current flowing through the circuit, i= 2A
Formula used:
When the battery is charging the potential difference, V across the cell can be written as,
Where ‘E’ is the emf of the cell and ‘r’ is internal resistance of the cell.
Solution:
As the battery is getting charged, the internal resistance can be calculated from the eqn.1, as
And by substituting the given values,
Hence the internal resistance of the cell is 0.6Ω
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