Find the charge on the capacitor shown in figure.


Concepts/Formulas used:


Ohm’s Law:


Potential Difference (V) across a resistor of resistance R when current I passes through it is given by Ohm’s law:



Capacitance:


If two conductors have a potential difference V between the them and have charges Q and -Q respectively on them, then their capacitance is defined as



At steady state, no current passes through 6μF . Hence, we can ignore the capacitor to find the equivalent resistance.


Now, 10Ω and 20Ω are in series.



The current is given by Ohm’s law:



Now, this is the same current that passes through 10Ω resistor.


The potential across it is given by:



Now, as the capacitor is in parallel with the 10Ω resistor the,



Now,





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