Find the charge on the capacitor shown in figure.
Concepts/Formulas used:
Ohm’s Law:
Potential Difference (V) across a resistor of resistance R when current I passes through it is given by Ohm’s law:
Capacitance:
If two conductors have a potential difference V between the them and have charges Q and -Q respectively on them, then their capacitance is defined as
At steady state, no current passes through 6μF . Hence, we can ignore the capacitor to find the equivalent resistance.
Now, 10Ω and 20Ω are in series.
The current is given by Ohm’s law:
Now, this is the same current that passes through 10Ω resistor.
The potential across it is given by:
Now, as the capacitor is in parallel with the 10Ω resistor the,
Now,