A capacitor of capacitance 10 μF is connected to a battery of emf 2V. It is found that it takes 50 ms for the charge on the capacitor to become 12.6 μC. Find the resistance of the circuit.
Concepts/Formulas used:
Charging a capacitor:
A capacitor of capacitance C is being charged using a battery of emf ϵ through a resistance R . A switch S is also connected in series with the capacitor. The switch is initially open. The capacitor is uncharged at first. At t=0, the switch is closed
The charge is at any t>0 is given by:
Note that is known as time constant.
Given,
Capacitance,
EMF of battery,
Resistance,
We also know that at ,
We know that,
Taking natural logarithm on both sides, we get
Now,