A 20 μF capacitor is joined to a battery of emf 6.0 V through a resistance of 100 Ω. Find the charge on the capacitor 2.0 ms after the connections are made.
Concepts/Formulas used:
Charging a capacitor:
A capacitor of capacitance C is being charged using a battery of emf ϵ through a resistance R . A switch S is also connected in series with the capacitor. The switch is initially open. The capacitor is uncharged at first. At t=0, the switch is closed
The charge is at any t>0 is given by:
Note that is known as time constant.
Given,
Capacitance,
EMF of battery,
Resistance,
Now,
Also,
We know that,
At t = 2.0ms,
Hence, the charge on the capacitor at t = 2.0ms is 76μC.