A 20 μF capacitor is joined to a battery of emf 6.0 V through a resistance of 100 Ω. Find the charge on the capacitor 2.0 ms after the connections are made.

Concepts/Formulas used:


Charging a capacitor:


A capacitor of capacitance C is being charged using a battery of emf ϵ through a resistance R . A switch S is also connected in series with the capacitor. The switch is initially open. The capacitor is uncharged at first. At t=0, the switch is closed


The charge is at any t>0 is given by:



Note that is known as time constant.


Given,


Capacitance,


EMF of battery,


Resistance,


Now,






Also,




We know that,



At t = 2.0ms,





Hence, the charge on the capacitor at t = 2.0ms is 76μC.


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