The needle of a dip circle shows an apparent dip of 45° in a particular position and 53° when the circle is rotated through 90°. Find the true dip.
If δ1andδ2be the apparent dips shown by the dip circle in the 2 perpendicular positions
δ 1 = 45° and δ2 = 53°
To find δ
the true dip (δ) is given by
1