A moving-coil galvanometer has a 50-turn coil of size 2 cm × 2 cm. It is suspended between the magnetic poles producing a magnetic field of 0.5 T. Find the torque on the coil due to the magnetic field when a current of 20 mA passes through it.
Given,
number of turns in the coil n=50
area of the cross section of the coil, A = 4 cm2
magnetic field strength due to the presence of the pole B =0.5 T
current flow through the coil I =20mA = 20X10-3
ζ=?
1