The potential difference applied to an X-ray tube is increased. As a re sult, in the emitted radiation,

Question

Philoid · Accepted Answer

From the equation of cut-off wavelength:

where, λ_min is the cut-off wavelength, h is the Planck’s constant (6.62607004 × 10^-34 m² kg / s), c is the speed of light in vacuum, e is the charge of the electron and V is the potential difference applied at the ends of the tube
Increasing the potential (V) will decrease the minimum wavelength. Hence, option (D) is correct.
Intensity depends on the heating current. As this is not changed, Intensity is unchanged. So, (C) is correct.

The potential difference applied to an X-ray tube is increased. As a result, in the emitted radiation,