The distance between the cathode (filament) and the target in an X-ray tube is 1.5 m. If the cutoff wavelength is 30 pm, find the electric field between the cathode and the target.
Given:
Distance between the filament and the target in the X-ray tube d=1.5m
cut-off wavelength= 30pm
Energy(E) is given by
thus,
Now,
Electric field = V/d=
=