The short-wavelength limit shifts by 26 pm when the operating voltage in an X-ray tube is increased to 1.5 times the original value. What was the original value of the operating voltage?
Given:
Let
be the initial wavelength, V be the initial potential
Hence,
be the new wavelength and V’ be the new operating voltage
When the operating voltage of the X-ray tube is increased to 1.5 times
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V- operating potential
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Therefore the initial wavelength is ![]()
Now, the operating voltage V is given by
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