The wavelength of K α X-ray of tungsten is 21.3 pm. It takes 11.3 keV to knock out an electron from the L shell of a tungsten atom. What should be the minimum accelerating voltage across an X-ray tube having tungsten target which allows production of K α X-ray?

Question

Philoid · Accepted Answer

Given:

wavelength of X-ray = 21.3 pm

Energy required to knock out an electron from L-shell = 11.3 KeV

and the voltage required= 11.3 kV

The energy gap between K and L shell, is given by

Thus the accelerating voltage across the X-ray tube for the production of ray is

V_k=69.609 keV

The wavelength of Kα X-ray of tungsten is 21.3 pm. It takes 11.3 keV to knock out an electron from the L shell of a tungsten atom. What should be the minimum accelerating voltage across an X-ray tube having tungsten target which allows production of Kα X-ray?

The wavelength of K_α X-ray of tungsten is 21.3 pm. It takes 11.3 keV to knock out an electron from the L shell of a tungsten atom. What should be the minimum accelerating voltage across an X-ray tube having tungsten target which allows production of K_α X-ray?