A certain element emits Kα X-ray of energy 3.69 keV. Use the data from the previous problem to identify the element.

Given:


Energy of Kα X-rays= 3.69 KeV or 3690 eV


we’re asked to identify the element which exhibits this behavior,


Wavelength is given by




Using Moseley’s law √c/ = α(Z – b),






Which gives us,



Z=20.17 (atomic number) which can be approximated to Z=20


Therefore, the element with z=20 is calcium (Ca)


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