Δfof formation of CH4 (g) at certain temperature is –393 kJ mol–1. The value of Δf is
Reason: C (s) + 2H2 (g) → CH4 (g)
Δf = Δf + ΔngRT
Δng= 1-2= -1
Substituting the value of Δng, above equation will become
Δf = Δf- RT
As temperature and gas constant both have a positive value, so the value of Δf will become more negative.
of formation of CH4 (g) at certain temperature is –393 kJ mol–1. The value of Δf
is
of formation of CH4 (g) at certain temperature is –393 kJ mol–1. The value of Δf is