At 298 K. K p for the reaction N 2 O 4 (g) ⇋ 2NO 2 (g) is 0.98. Predict whether the reaction is spontaneous or not.

Question

Philoid · Accepted Answer

o Spontaneity depends on the sign of Gibb’s free energy G of a reaction and it’s a relation with K_p, the equilibrium constant at constant pressure is: ∆_RG = - RT ln K_p

For the given reaction N₂O₄ (g) ⇋2NO₂ (g) the value of K_p = 0.98.

Hence, ∆_rG⁰ = - RT ln(0.98)

Since , ln(0.98) has a negative value , the value of ∆_rG⁰ becomes positive. Therefore, the reaction is non- spontaneous

At 298 K. Kp for the reaction N2O4 (g) ⇋2NO2 (g) is 0.98. Predict whether the reaction is spontaneous or not.

At 298 K. K_p for the reaction N₂O₄ (g) ⇋2NO₂ (g) is 0.98. Predict whether the reaction is spontaneous or not.