Arrange the following complexes in the increasing order of conductivity of their solution: [Co(NH3)3Cl3], [Co(NH3)4Cl2] Cl, [Co(NH3)6]Cl3 , [Cr(NH3)5Cl]Cl2

Question

Philoid · Accepted Answer

The increasing order of conductivity is as follows:

[Co(NH₃)₃Cl₃]<[Co(NH₃)₄Cl₂]Cl< [Cr(NH₃)₅Cl]Cl₂<[Co(NH₃)₆]Cl₃

These complexes have 0,1,2 and 3 free chlorine ions outside the coordination sphere respectively. More free ions not bound to a complex, greater will be the conductivity.

Arrange the following complexes in the increasing order of conductivity oftheir solution: [Co(NH3)3Cl3], [Co(NH3)4Cl2] Cl, [Co(NH3)6]Cl3 , [Cr(NH3)5Cl]Cl2

Arrange the following complexes in the increasing order of conductivity of
their solution: [Co(NH3)3Cl3], [Co(NH3)4Cl2] Cl, [Co(NH3)6]Cl3 , [Cr(NH3)5Cl]Cl2