A coordination compound CrCl3.4H2O precipitates silver chloride when treated
with silver nitrate. The molar conductance of its solution corresponds to a
total of two ions. Write structural formula of the compound and name it.
If it forms silver chloride then there is one free chlorine atom outside the coordination sphere. The structural formula has to be [Cr(H2O)4Cl2]Cl.
There are one cation and one anion which corresponds to a total of two ions which show conductivity. The name of this complex is tetraaquadichlorido chromium(III) chloride.