Figure (3-Q5) shows the position of a particle moving on the X-axis as a function of time.

The slope of the given displacement-time graph gives the velocity of the particle. Since, the slope is zero 6 times; the particle has come to rest 6 times.


We can’t say that the slope is maximum at t=6 s and thus no comment on maximum speed.


Since the value of slope is changing, it can go negative as well as positive. Thus, the velocity does not remain positive for t=0 to t=6 s.


Since the initial displacement as well as final displacement is positive, the average velocity is always positive. Therefore, only option A is correct.

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