A train starts from rest and moves with a constant acceleration of 2.0 m/s2 for half a minute. The brakes are then applied and the train comes to rest in one minute. Find (a) the total distance moved by the train, (b) the maximum speed attained by the train and (c) the position(s) of the train at half the maximum speed.
a. Here initial velocity, u=0
Let v be the final velocity
Acceleration, a=2 m/s2
Now, at t=30 s
We know,
When breaks are applied u1=60 m/s
v1=0
t=60 s
Total distance moved is 
b. Maximum speed attained by the train is v= 60 m/s
c. Half the maximum speed=60/2=30 m/s
When acceleration of the train, a=2 m/s2
When the train is decelerating with, a1=-2 m/s2
Position from the starting point is 900+1350=2250 m=2.25 km
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