A ball is projected vertically upward with a speed of 50 m/s. Find (a) the maximum height, (b) the time to reach the maximum height, (c) the speed at half the maximum height. Take g = 10 m/s2.
Given, initial velocity, u=50 m/s
g=a=-10 m/s2
a. We know at highest point velocity, v=0
Also, distance s is
b. Time taken, t is
a. Here s=125/2=62.5 m
We know,
i.e.