A healthy young man standing at a distance of 7 m from an 11.8 m high building sees a kid slipping from the top floor. With what speed (assumed uniform) should he run to catch the kid at the arms height (1.8 m)?
Given:
Height of the building = 11.8 m
Distance of the young man from the building = 7 m
The kid should be caught over 1.8 m from ground.
As the kid is slipping, his initial velocity u is 0.
Acceleration, a = 9.8 m/s2
Let s be the distance before which the kid has to be caught:
S= 11.8 − 1.8 = 10 m
Using the equation of motion, we get:
So, t =1.42 sec
This is the time in which the man should reach the bottom of the building to catch the kid.
Velocity with which the man should run:
1