A ball is thrown at a speed of 40 m/s at an angle of 60o with the horizontal. Find (a) the maximum height reached and (b) the range of the ball. Take g = 10 m/s2.

Given:
Initial speed of the ball, u = 40 m/s
Angle of projection of the ball with the horizontal,
= 60°
Also,
a = g = 10 m/s2


(a) Maximum height reached by the ball:




(b) Horizontal range of the ball:




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