Two charged particles placed at a separation of 20 cm exert 20 N of Coulomb force on each other. What will be the force if the separation is increased to 25 cm?
Coulomb’s force between two charges is given by –
Where,
q1 and q2 = are the charges
k = proportionality constant = 9×109
r= distance between the charges
When, r= 20cm = 0.2m, Coulomb’s force = 20N
When r = 25cm
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