A constant force F=m 2 g/2 is applied on the block of mass m1 as shown in figure (5-E 10). The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m 1 .

Question

Philoid · Accepted Answer

Given: From the free-body diagram of block of mass m₁,

m₁a = T − F …(i)

From the free-body diagram of block of mass m₂,

m₂a = m₂g − T …(ii)

Adding both the equations, we get: a (m₁+ m₂) = m₂g - F

∴ F=

∴The acceleration of mass m₁, a= , towards the right.

A constant force F=m2g/2 is applied on the block of mass m1 as shown in figure (5-E 10). The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m1.

A constant force F=m₂g/2 is applied on the block of mass m1 as shown in figure (5-E 10). The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m₁.