In figure (5-E11) m1 = 5 kg, m2 = kg and F = 1 N. Find the acceleration of either block. Describe the motion of m if the string breaks but F continues to act.


Give:


m1= 5 kg, m2 = 2 kg and F = 1 N


Let the acceleration of the blocks be a.


From the free-body diagram, m1a = m1g + F − T …(i)


Again, from the free-body diagram, m2a = T − m2g − F …(ii)


Adding equations (i) and (ii), we have:



a= =4.2 m/s2


Hence, acceleration of the block is 4.2 m/s2.


After the string breaks, m1 moves downward with force F acting downward. Then,


m1a = F + m1g


5a = 1 + 5g



g = +0.2 m/s2


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