Calculate the tension in the string shown in figure (5-E13). The pulley and the string are light and all surfaces are frictionless. Take g = 10 m/s2.




Given:


Refer the above diagram for the FBD


T + ma =mg …(i)


And T = ma …(ii)


From equations (i) and (ii), we get:


ma + ma = mg


2ma = g


a= =5 m/s2


From equation (ii), T = ma = 5 N


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