A man stands before a large wall at a distance of 50.0 m and claps his hands at regular intervals. Initially, the interval is large. He gradually reduces the interval and fixes it at a value when the echo of a clap merges with the next clap. If he has to clap 10 times during every 3 seconds, find the velocity of sound in air.

Given:


Distance of large wall from the man S= 50 m


He has to clap 10 times in 3 sec


So, the time interval between two claps will be =


Therefore, time taken by the sound to reach the wall sec


We know that;




Therefore, the velocity of sound v= 333m/sec


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