Two successive resonance frequencies in an open organ pipe are 1944 Hz and 2592 Hz. Find the length of the tube. The speed of sound in air is 324 m s-1.

Given:
Velocity of sound in air



Let be the length of the resonating column.



Then, the frequencies of the two successive resonances will be:


And .


As per the question,




So,





Hence, the length of the tube is 25 cm.


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