The fundamental frequency of a closed pipe is 293 Hz when the air in it is at a temperature of 20oC. What will be its fundamental frequency when the temperature changes to 22oC?


Given:
The fundamental frequency of a closed pipe is 293 Hz. Let this be represented by
.
Temperature of the air in closed pipe
= 20°C = 20 + 273 = 293 K


Let
be the frequency in the closed pipe when the temperature of the air is .



= 22°C = 22 + 273 = 295 K


Relation between and :






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