A piano wire A vibrates at a fundamental frequency of 600 Hz. A second identical wire B produces 6 beats per second with it when the tension in A is slightly increased. Find the ratio of the tension in A to the tension in B.


Mass per unit length of both the wires = m

Fundamental frequency of wire of length and tension is given by:



It is clear from the above relation that as the tension increases, the frequency increases.


Fundamental frequency of wire A is given by:



Fundamental frequency of wire B is given by:



It is given that 6 beats are produced when the tension in A is increased.



Therefore, the ratio can be obtained as:






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